Prove that If a ray stands on a line then the sum of the adjacent angles so formed is 180°.
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Answered by
38
Hey mate!
The answer is given below :
When a ray stands on a line, two adjacent angles are formed.
We know that the angle lying on a straight line is 180°.
The two angles being adjacent, make a total angle of 180° on the straight line.
Another way, we can see since the ray stands on the straight line, we can consider it is a perpendicular line.
Thus, the two adjacent angles are right angles.
So, the total angle
= 90° + 90°
= 180°
(Referred to the given attachment.)
The answer is given below :
When a ray stands on a line, two adjacent angles are formed.
We know that the angle lying on a straight line is 180°.
The two angles being adjacent, make a total angle of 180° on the straight line.
Another way, we can see since the ray stands on the straight line, we can consider it is a perpendicular line.
Thus, the two adjacent angles are right angles.
So, the total angle
= 90° + 90°
= 180°
(Referred to the given attachment.)
Attachments:
Answered by
76
A ray CD stands on a line AB such that /_ACD and /_ BCD are formed.
To Prove : /_ ACD + /_ BCD = 180°
Construction : Draw CE Perpendicular AB.
Proof : /_ ACD = /_ ACE + /_ ECD ----(1)
And,
/_ BCD = /_ BCE - /_ ECD -------(2)
Adding (1) and (2) , we get :
/_ ACD + /_ BCD = ( /_ ACE + /_ECD ) + ( /_ BCE - /_ ECD ) = ( /_ ACE + /_ BCE ) = ( 90° + 90° ) = 180 [ Since /_ ACE = /_BCE = 90° ]
Hence,
/_ ACD + /_ BCD = 180°
To Prove : /_ ACD + /_ BCD = 180°
Construction : Draw CE Perpendicular AB.
Proof : /_ ACD = /_ ACE + /_ ECD ----(1)
And,
/_ BCD = /_ BCE - /_ ECD -------(2)
Adding (1) and (2) , we get :
/_ ACD + /_ BCD = ( /_ ACE + /_ECD ) + ( /_ BCE - /_ ECD ) = ( /_ ACE + /_ BCE ) = ( 90° + 90° ) = 180 [ Since /_ ACE = /_BCE = 90° ]
Hence,
/_ ACD + /_ BCD = 180°
Attachments:
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