prove that if a side of a triangle is produced then the exterior angle so formed is equal to the sum of two interior opposite angles
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in a triangle ∆ABC
E is produced on BC
IN ∆ABC
<BAC + <ACB + <CBA = 180
( sum of angle property) (1)
<ACB + <ACE = 180
( LINEAR PAIR ) (2)
eq1 and eq2 is equal to 180
<BAC + <ACB+ <CBA = <ACB + <ACE
<ACB will be cut from both side
<BAC + <CBA = <ACE
hence proved
E is produced on BC
IN ∆ABC
<BAC + <ACB + <CBA = 180
( sum of angle property) (1)
<ACB + <ACE = 180
( LINEAR PAIR ) (2)
eq1 and eq2 is equal to 180
<BAC + <ACB+ <CBA = <ACB + <ACE
<ACB will be cut from both side
<BAC + <CBA = <ACE
hence proved
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awesomeakshay:
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Answered by
1
Given: angle p+q+r=180°
to prove: angle s =p+q
proof: angle r+ angle s=180°(linear pair)---1
angle p+q+r=180°(angle sum property)---2
from 1 and 2
r+s=p+q+r
hence, r=r
s=p+q. proved
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