prove that if chords of congruent circles spend equal angles at the centre then the chords are equal
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Let us consider two congruent circles (circles of same radius) with centres as O and O'.
In ΔAOB and ΔCO'D,
∠AOB = ∠COD (Given)
OA = OC (Radii of congruent circles)
OB = OD (Radii of congruent circles)
∴ ΔAOB ≅ ΔCOD (SAS congruence rule)
⇒ AB = CD (By CPCT)
Hence, if chords of congruent circles subtend equal angles at their centres, then the chords are equal.
HOPE THIS HELPS YOU!!! ❤❤❤
Let us consider two congruent circles (circles of same radius) with centres as O and O'.
In ΔAOB and ΔCO'D,
∠AOB = ∠COD (Given)
OA = OC (Radii of congruent circles)
OB = OD (Radii of congruent circles)
∴ ΔAOB ≅ ΔCOD (SAS congruence rule)
⇒ AB = CD (By CPCT)
Hence, if chords of congruent circles subtend equal angles at their centres, then the chords are equal.
HOPE THIS HELPS YOU!!! ❤❤❤
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naaz26:
thanx alot
Answered by
4
Answer:
Consider two congruent circles with centres as O and O
In AOB andCOD,
L AOB = L COD(given )
OA= OC(radius)
OB=OD(radius)
By SAS congruent rule
AOB=~ COD
Therefore, AB=CD(CPCT)
Hence, if chords of congruent circles subtend equal angles at their centres, then the chords are equal
Hope it may help you if it make it as brainliest°°°°....❤️❤️❤️
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