Question

prove that if chords of congruent circles subtend equal angles at their centers, then the chords are equal....

Plz help me to solve this is v.imp.for me.......

Answer 1

Answer:

Let us consider two congruent circles (circles of same radius) with centers as O and O

In ΔAOB and ΔCO'D,

AOB = CO'D (Given)

OA = O'C (Radii of congruent circles)

OB = O'D (Radii of congruent circles)

ΔAOB ΔCO'D (SAS congruence rule)

AB = CD (By CPCT)

Hence, if chords of congruent circles subtend equal angles at their centers, then the chords are equal

Hope it helps

Answer 2

Explanation:

AOB=CO'D

OA=OC

OB=O'D(RADII)

AOB = COD

AB=CD(CPCT)