Question

Prove that if chords of congruent circles subtend equal angles at their centres, then
the chords are equal.​

Answer 1

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Answer 2

ANsWeR :-

In ∆ AOB & ∆ PXQ ,

AO = PX [ Radius of the circle ]

∠AOB = ∠PXQ [ Triangles are equal ]

BO = XQ [ Radius of the circle ]

∆ AOB ≈ ∆PXQ ( SAS rule )

Hence , AB = PQ [ CPCT ]

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