Prove that if chords of congruent circles subtend equal angles at their centres, then the chords are equal.
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In △AOB and △PXQ
AO=PX [Radius of congruent circles are equal]
∠AOB=∠PXQ [Given]
BO=QX [Radius of congruent circles are equal]
△AOB≅△PXQ [SAS congruence rule]
AB=PQ [CPCT]
Step-by-step explanation:
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