solve this problem find remaining angles
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Step-by-step explanation:
ACE= BAC= 50° (AB||CE and ACE and BAC are alternate angles which are same)
ACE+ECD+ACB= 180°
ACB= (180-50-60)°= 70°
In ∆ABC,
ABC+ACB+BAC= 180° (Sum of all interior angles of a triangle is always 180°)
ABC= (180-70-50)°= 60°
ABC= 60°, ACB= 70°, BAC= 50°..
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