prove that if in 2 triangles,sides of one triangle are in same ratio of sides of the other triangle,then their corresponding angles are equal
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The answer of u r question is.....
Ans:
given,
triangle ABc and triangle DEF are such that
AB/DE = BC/EF = CA/FD (1)
RTP: <À=<D,<B=<E,<C=<F.....
PROOF:
DP/PE= DQ/QF AND PQ ll EF (CONVERSEOF BBT)
SO,
<P = <E AND <Q=<F
DP/DE = DQ/DF = PQ/EF
SO
BC=PQ
TRIANGLE ABC IS CONGRUENT TO TRIANGLE DPQ...
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