Prove that if r is less than or equal to s and s is less than or equal to n then p(n,s) is divisible by p(n,r)
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Answer:
n! = n!
(n−r)!
∴(n−r)!=(n−s)!
Given r<s⟹−r>−s
∴(n−r)>(n−s)
We know that two different factorials are zero and one
∴n−r=1andn−s=0
∴r=n−1,s=n
∴r+s=2n−1
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