Math, asked by Anonymous, 10 days ago

Prove that :-

If {\bf \{ f_{n} \}} be a sequence of real functions which converge uniformly to \bf f on the interval {\bf a \leqslant x \leqslant b} also suppose that each function {\bf f_{n} ( n = 1 , 2 , 3 \cdots \cdots )} is continuous on {\bf a \leqslant x \leqslant b} . Then for every  \alpha and  \beta such that {\bf a \leqslant \alpha < \beta \leqslant b} . Then ;

{\boxed{\displaystyle \bf \lim_{n \to \infty} \displaystyle \bf \int_{\alpha}^{\beta} f_{n} (x ) dx = \displaystyle \bf \int_{\alpha}^{\beta} \displaystyle \lim_{n \to \infty} \bf f_{n} (x ) dx}}

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Answered by βαbγGυrl
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Refer the attachment:)

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Answered by MissQueenOfFashion
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