Prove that if the diagonals of a quadrilateral bisect each other, then it is a parallelogram.
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selected Jun 14, 2018 by Golu Given: A quadrilateral ABCD whose diagonals AC and BD bisect each other at point O. i.e., OA = OC and OB = OD To prove: ABCD is a parallelogram i.e., AB ║ DC and AD ║ BC. Proof: In ∆AOB and ∆COD OA = OC [Given] OB = OD [Given} And, ∠AOB = ∠COD [Vertically opposite angles] ⇒ ∆AOB ≅ ∆COD [By SAS] ⇒ ∠1 = ∠2 [By cpctc] But these are alternate angles and whenever alternate angles are equal, the lines are parallel. ∴ AB is parallel to DC i.e., AB ║ DC Similarly, ∆AOD ≅ ∆COB [By SAS] ⇒ ∠3 = ∠4 But these are also alternate angles ⇒ AD ║ BC AB ║ DC and AD ║ BC ⇒ ABCD is a parallelogram.
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