Prove that in a hexagon the sum of the vectors drawn to its vector from the origin is zero
Answers
in a Hexagon Vector Drawn from each vertex to center would be = 0
Step-by-step explanation:
in Hexagon all internal angles are 120°
Vector Drawn from each vertex to center would be ( A is side of Hexagon or Radius of circum circle of hexagon)
A∠60 = ACos60 + iAsin60 = A/2 + i√3/2A
A ∠120 = ACos120 + iAsin120 = -A/2 + i√3/2A
A∠180 = ACos180 + iAsin190 = -A
A∠240 = ACos240 + iAsin240 = -A/2 - i√3/2A
A∠300 = ACos300 + iAsin300 = A/2 - i√3/2A
A∠360 = A∠0 = A
Addding all
A/2 + i√3/2A -A/2 + i√3/2A -A - A/2 - i√3/2A + A/2 - i√3/2A
= 0
Vector Drawn from each vertex to center would be = 0
Answer:
let the origin of hexagon be O
thus,
OA=-OD
OB=-OE
OC= -OF
The sum of all the vectors drawn from the center of regular hexagon to it's vertices is
=OA+OB+OC+OD+OE+OF
=-OD-OE-OF+OD+OE+OF
=0
Hence, the sum of vectors drawn to it's vertices from the origin is ZERO
HENCE PROVED