prove that in a parallelogram opposite sides are equal
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Answered by
141
Consider a parallelogram ABCD.
AC and BD are the diagonals of the parallelogram.
Each diagonal of the parallelogram divides the parallelogram into two congruent triangles.
ΔADC ≅ ΔABC
∴ Corresponding sides of congrunt triangles are equal.
⇒CD = AB
⇒ AD = BC
Hence the opposite sides of the parallelogram are equal.
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Answered by
97
Statement : In a parallelogram, opposite angles are equal.
Given : Parallelogram ABCD
To prove ; ∠A = ∠C and ∠B = ∠D
Proof :
In parallelogram ABCD,
Consider,
AD || BC and AB is transversal
∠A + ∠B = 180° [Co - int. Angles]...... (i)
Now, consider AB || DC and BC transversal
∠B + ∠C = 180° [Co - int. Angles]...... (ii)
From (i) and (ii) we get ;
∠A + ∠B = ∠B + ∠C
∠A = ∠C
∠B = ∠D
Hence, it is proved.
Given : Parallelogram ABCD
To prove ; ∠A = ∠C and ∠B = ∠D
Proof :
In parallelogram ABCD,
Consider,
AD || BC and AB is transversal
∠A + ∠B = 180° [Co - int. Angles]...... (i)
Now, consider AB || DC and BC transversal
∠B + ∠C = 180° [Co - int. Angles]...... (ii)
From (i) and (ii) we get ;
∠A + ∠B = ∠B + ∠C
∠A = ∠C
∠B = ∠D
Hence, it is proved.
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