Question

prove that in a parallelogram,the lines joining a pair of opposite vertices to the mid point of a pair of opposite sides trisect a diagonal .no spamming​

Answer 1

Answer:

Hey mate plzz refer to the attachment

Answer 2

Step 1:

In parallelogram ABCD, E is the mid-point of AB and F is the mid-point of DC. Also AB || DC.

Step 2:

AB = DC and AB || DC

∴ (1/2) AB = (1/2) DC and AE || DF (Since E and F mid point of AB and DC)

∴ AE = (1/2) AB and DF = (1/ 2 ) DC

∴ AE = DF and AE || DF

Step 3:

Now parallelogram AEFD and EBCF are on equal bases DF = FC and between two parallels AB and DC

∴ ar ( || gm AEFD) = ar ( || gm EBCF)