prove that 'in a quadrilateral, the sum of exterior angles is 360?
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⟹∠DAC+∠ADC+∠DCA=180°
Similarly, ∠CAB+∠ABC+∠BCA=180°
⟹∠DAC+∠ADC+∠DCA+∠CAB+∠ABC+∠BCA=180°+180°
⟹(∠DAC+∠CAB)+(∠BCA+∠DCA)+∠ADC+∠ABC=360°
⟹∠DAB+∠BCD+∠CDA+∠ABC=360°
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