Question

prove that in a rectangle is a cyclic quadrilateral

Answer 1

Hyy

We know that ..

Each angle of a rectangle is a right angle.

Therefore ,

Sum of oppsite angles of a rectangle is supplementary i.e., 180°

For a cyclic quadrilateral, sum of opposite angles is 180°.

=> 90° + 90° = 180° ( sum of opposite angles of a rectangle ).

Hence, rectangle is a cyclic quadrilateral.

Thank you

Answer 2

Hello mate ☺

____________________________

Solution:

➡It is given that parallelogram ABCD is cyclic. We need to prove that ABCD is a rectangle.

∠B=∠D   (Opposite angles of a parallelogram are equal) ....(1)

∠B+∠D=180°   ...... (2)  

(Sum of opposite angles of a cyclic quadrilateral is equal to 180°)                    

Using equation (1) in equation (2), we get

∠B+∠B=180°

⇒2∠B=180°

⇒∠B=180/2=90°      …...(3)

➡Therefore, ABCD is a parallelogram with ∠B=90° which means that ABCD is a rectangle.

I hope, this will help you.☺

Thank you______❤

_____________________________❤h