Prove that in a right angle triangle square of the hypotenuse is equal to the sum of the square of other two sides
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given that in triangle abc right angled at b RTP RTP AC square is equals to a b square + BC square construction draw BD perpendicular to AC proof in triangle abc and triangle abc angle A is equals to angle A common angle abc is equals to angle abc is 90° therefore triangle ABC is congruent congruent to triangle abc by a a coronary ADB a b is equals to ab by AC
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