Prove that in a right angled Isosceles triangle, the square on hypotenuse is twice the square of one of the other two sides.
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In a right angle triangle, square of hypotenuse is twice the product of other two sides. Both the sides of the right angle triangle are equal. In ΔABC angles opposite to these sides will be equal. Therefore, one angle of the triangle is 45°
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Hey Shaurya Kesa hai Mai Kunwar
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