Prove that in a right angled triangle the square of the hypotenuse is equal to the sum of the squares of the other two sides. Using the above do the following: Prove that in a ∆ABC, if AD is perpendicular to BC, then Asquare + Csquare = Asquare + Bsquare .
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We know that if a perpendicular is drawn from the vertex of a right angle of a right angled triangle to the hypotenuse, than triangles on both sides of the perpendicular are similar to the whole triangle and to each other.We have,△ADB∼△ABC. (by AA similarity)Therefore, AD/AB=AB/AC(In similar Triangles corresponding sides are proportional)AB²=AD×AC……..(1)Also, △BDC∼△ABCTherefore, CD/BC=BC/AC(in similar Triangles corresponding sides are proportional)²
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