Question

prove that in a right triangle the square of hypotenuse is equal to the sum of the square of the other two side​

Answer 1

Step-by-step explanation:

In a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the remaining two sides.

To understand it better we break down the statement.

A right-angled triangle is a triangle with a 90-degree angle.

The hypotenuse is the longest side of the right-angled triangle.

The remaining sides of the triangle are called the base and the perpendicular.

Pythagoras Theorem

In the diagram above,

∠ABC is a right angle.

AC is the hypotenuse.

AB is known as the perpendicular.

BC is the base.

So according to the Pythagoras Theorem,

(AC)²=(AB)²+(BC)²

But then should we merely trust a single statement? I don’t think so. We need a proof!

Answer 2

Answer:

Step-by-step explanation:

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