Question

Prove that in a right triangle, the square on the hypotenuse is
equal to the sum of the squares on the other two sides .In ∆ABC,

AD perpendicular to BC

and CD=1/3BD. Using
the above theorem, Prove that

2AB^2 = 2AC^2 + BC^2

Answer 1

Answer:

Theorem 1: In a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. ... To Prove: (Hypotenuse)2 = (Base)2 + (Perpendicular)2. i.e., AC2 = AB2 + BC2. Construction: From B draw BD ⊥ AC.