Question

prove that in a square .diagonals are equal​

Answer 1

Answer:

Hii buddy!

Let ABCD be a square. Let the diagonals AC and BD intersect each other with at a point 0. To prove that the diagonals of a square are equal and bisect each other at right angles, we have to prove AC = BD, OA = OC, OB = OD, and AOB = 90°.

In ABC and DCB,

AB = DC ( sides of a square are equal to each other)

ABC = DCB ( all interior angles are of 90)

BC = CB ( Common side)

ABC = DCB ( By SAS congruency)

AC = DB ( By CPCT)

Here, the diagonals of a square are equal in length.

In AOB and COD,

AOB = COD ( vertically opposite angles)

ABO = CDO ( vertically opposite angles)

AB = CD ( sides of a square are always equal)

AOB = COD ( By AAS congruency)

AO = CO and OB = OD ( By CPCT)

Hence, the diagonals of a square bisect each other.

In AOB and COB,

As we had proved that diagonals bisect each other, therefore,

AO = CO

AB = CB ( sides of a square are equal)

BO = BO ( common)

AOB = COB ( By CPCT)

However, AOB = COB = 180 ( linear pair)

2 AOB = 180°

AOB = 90°

Hence, the diagonals of a square bisect each other at right angle.

I hope this will be you, dude!

Answer 2

Answer:

Sorry but mai I.n.st.a. par nahi hu