Question

Prove that in an isoscales triangle the median
passing through the vertex common to equal
sides of the triangle is perpendicular to the base.​

Answer 1

Answer:

let ∆ABC is an isosceles triangle

seg AB is congruent to seg AC

seg AD is a median

∆ADB is congruent to ∆ADC

by SSS test

angle ADB is congruent to angle ADC

ADB+ADC=180°

angles in linear pair

ADB+ADC=180°

2ADC=180°

ADC=ADB=90°

seg AD is perpendicular to seg BC