Question

prove that in an isosceles triangle opposite angles of two equal sides are equal

Answer 1

Consider a triangle ABC. Where AB=AC.
construction - draw AD perpendicular to base BC
Now in triangle ABD AND ACD
AB=AC(GIVEN)
AD=AD(COMMON)
ANGLE ADB=ANGLE ADC(each 90 degree)
Therefore triangle ABD IS CONGRUENT TO TRIANGLE ACD
THEREFORE ANGLE =ANGLE C(C. P. C. T)
HENCE PROVED
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Answer 2

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