Prove that in any triangle the sum of the squares of the diagonal of a parallelogram is equal to the sum of the square of its sides
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using pythagoras theorem a equals 3 , b equals 4 and c equals 5
a ^2 + b^2 : c^2
lhs : sides
rhs : diagonal
now 3^2 + 4^2 :5^2
9+16 : 25
proved
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a ^2 + b^2 : c^2
lhs : sides
rhs : diagonal
now 3^2 + 4^2 :5^2
9+16 : 25
proved
plz mark as brainliest
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