prove that is irrational
![\sqrt{2} \sqrt{2}](https://tex.z-dn.net/?f=++%5Csqrt%7B2%7D+)
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Answer:
Find the square root of √2 by division method.
You will find that the quotient is non-terminating and non-recurring also.
The properties to be a irrational number is to be a non-recurring and non terminating.
Therefore, √2 is a irrational number.
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