Prove that log a, log ab , log ,(ab) square is an A. P. Find its nth term.
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log a = log a
log ab =log a + log b
log ab²= 2(log a + log b)
a =log a, d=log a + log b -log a
=log b
d =2(log a + log b) -log a + log b
= log a + log b
Therefore it is not an AP as d is not constant
log ab =log a + log b
log ab²= 2(log a + log b)
a =log a, d=log a + log b -log a
=log b
d =2(log a + log b) -log a + log b
= log a + log b
Therefore it is not an AP as d is not constant
mili1978piku2:
Then, what is the answer
No
Thanks
U look. Welcome
But d is constant
let's check, if anyone else answer
Here in this sequences d is not constant therefore it is not an AP
OK OK thanks
I understood
U r welcome
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