two opposite angles of a parallelogram are (3x-2) degree and (50-x) degree. find the measure of each angle of the parallelogram?
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Given two opposite angles of a parallelogram are (3x − 2)º and (50 − x)º
Recall that opposite angles of a parallelogram are equal.
Hence (3x − 2) = (50 − x)
⇒ 3x + x = 50 + 2
⇒ 4x = 52
∴ x = 13
(3x − 2)º = [3(13) − 2]º = [39 − 2]º = 37º
Sum of adjacent angles is 180º
Hence other two equal opposite angles = 180º − 37º = 143°
Recall that opposite angles of a parallelogram are equal.
Hence (3x − 2) = (50 − x)
⇒ 3x + x = 50 + 2
⇒ 4x = 52
∴ x = 13
(3x − 2)º = [3(13) − 2]º = [39 − 2]º = 37º
Sum of adjacent angles is 180º
Hence other two equal opposite angles = 180º − 37º = 143°
Answered by
3
HEYA.....✌✌✌
HERE IS YOUR ANSWER.........
we know that the opposite angles of a parallelogram ate equal
And hence
3x-2=50-x
3x+x=50+2
4x=52
x=13
HERE IS YOUR ANSWER.........
we know that the opposite angles of a parallelogram ate equal
And hence
3x-2=50-x
3x+x=50+2
4x=52
x=13
gmamadhumita3:
The measure of 1st angle
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