prove that n(aub)=n(a)+n(b)-n(anb)
help me plzz
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let a=c+x,b=d+x ,where n(anb)=x
n(aub)=c+d+x
=(c+x)+(d+x)-x
=n(a)+n(b)-n(anb)
n(aub)=c+d+x
=(c+x)+(d+x)-x
=n(a)+n(b)-n(anb)
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