prove That,
n^Cr-1 + 2n^Cr-2 + n^Cr-3 = n+2^Cr-1
___________
chp: Permutation and combination.
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Answer:
Step-by-step explanation:
Here, we will use the property of binomial coefficients,
nCr+nCr−1=(n+1)Cr
L.H.S.=nCr+2⋅nCr−1+nCr−2
=nCr+nCr−1+nCr−1+nCr−2
Using the above property,
=(n+1)Cr+(n+1)Cr−1
Again using the above property,
=(n+2)Cr=R.H.S.
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