Prove that no matter what is the real number a and b are, the sequence with nth term a+nb is always an A.P. What is the common difference?
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No matter what is the real number a and b, sequence with nth term a+nb is always an AP.
- Let nth term Tn=a+nb.
- Since the nth term depends linearly on n, we conclude that sequence is an Arithmetic Progression (AP).
- The common difference (d) = nth term - (n+1)th term = (a+nb) - (a+(n-1)b) = b
Hence, common difference = b.
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