Question

prove that no matter what the real numbers a and b are, the sequence with nth term a +nb is always an A.P. what is the common difference....
plz answer this question on a paper.....​

Answer 1

Heya friends!!

.

I think it's too easy ☺..

let the nth term of a given profession be given by

.tn=an+b. 【where a and b is constant 】

=)then ,tn-1=a(n-1)+b

=)tn-1 =an+b-a.

now ,there is two term let tn-1 is first term and tn is first term of an Ap.

【like t2-t1=d 】simularly here

so,tn-tn-1=d

so,an+b-an-b+a

=)a is common difference ,which is constant ,

hence the given progession is in an Ap

hope it help you 1☺

Answer 2

Answer:

hope you understood

Step-by-step explanation:

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