prove that nsquare - n is divisible by 2 for every positive integer n
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n^2-n
n(n-1)
Now two cases are possible
1→n is even
So n is divisible by 2, hence the given number is also divisible by 2
2→n is odd
so n-1 is even, hence again the given number is divisible by 2
So in both cases n^2-n is divisible by 2
n(n-1)
Now two cases are possible
1→n is even
So n is divisible by 2, hence the given number is also divisible by 2
2→n is odd
so n-1 is even, hence again the given number is divisible by 2
So in both cases n^2-n is divisible by 2
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