Question

prove that of any two chords of a circle then the one which is larger is nearer to the centre

Answer 1

heychere it is...
in the pic...
hope this helps...

Answer 2

Step-by-step explanation:

Consider above the circle, Consider two chords AB,CD.

at distance a,b respectively.

let AB=2l

1

CD=2l

2

from the figure, a

2

+l

1

2

=r

2

−−−(1)

a

2

=r

2

−l

1

2

−−−−(2)

b

2

+l

2

2

=r

2

b

2

=r

2

−l

2

2

−−−−−(3)

a

2

>b

2

∴r

2

−l

1

2

>r

2

−l

2

2

∴l

2

2

>l

1

2

⇒l

2

>l

1

a>b⇒ chord AB is farther

chord CD the nearer chord is longer (∴l

2

>l

1

)