prove that om bisect ab if om is perpendicular to ab
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Look at triangles OAM and OBM.
The hypotenuses (OA and OB) are the same, as they are both the radius of the circle.
OM is common to both triangles.
OMA and OMB are both right angles.
Triangles OAM and OBM are congruent (RHS), so it follows that AM = MB.
Therefore, M is the midpoint of AB, and the chord has been bisected.
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the above proves that on is perpendicular to ab
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