Question

prove that one and only one of n , n + 4 , n+8 , n+12 and n+16 is divisible by 5 , where n is any positive integer? Is there anyone what can answer this out ill mark him/her as a brainalist!​

Answer 1

Answer:

I know the answer

Step-by-step explanation:

Given numbers are n, (n+ 4), (n + 8), (n + 12) and (n + 16), where n is any positive integer.

Then, let n = 5q, 5g + 1, 5g + 2, 5g + 3, 5q + 4 for q∈ N [by Euclid’s algorithm]

Then, in each case if we put the different values of n in the given numbers. We definitely get one and only one of given numbers is divisible by 5.

Hence, one and only one out of n, n+ 4, n+ 8, n+12 and n+16 is divisible by 5.