Question

The sum of three consecutive integers is 48.find the number

Answer 1

Answer:

let the first consecutive no b x ,2nd x+1 and 3rd b x+2

according to the question

x+x+1+x+2= 48

3x+3= 48

3x= 45

hence x=15

Answer 2

Answer:

Step-by-step explanation:

Let the 3 consecutive number be x ,(x+1), (x+2)

ATQ-

X+(x+1)+(x+2) = 48

X+x+1+x+2 = 48

3x+3 = 48

3x = 48- 3

3x = 45

X = 45÷3

X = 15

Numbers-

X,(x+1),(x+2)

15,16,17

Answer : 15,16,17