Question

prove that one of any three consecutive positive integes must be divisible by 3

Answer 1

hii!!!!
there is your answer
??
let 3 consecutive positive integers be P, P+1and P+2
whenever a number is divided by 3 , the remainder we get is either,0 or 1, or 2 .
:
therefore,
P=3q or 3q+1 3q+2 , where q is some integer
if P= 3q, then n is divisible by 3
if P = 3q +1, then n+2 =3q +1+2 =3q +3 =3( q+1) is divisible by 3
if P = 3q+2 ,then n +1 = 3q+2 +1= 3q+3 =3 ( q+1 ) is divisible by 3
thus ,we can state that one of the number among P,p+ 1&p+2 is always divisible by 3
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