Question

prove that one of every three consecutive positive integer is divisible by 3​

Answer 1

Step-by-step explanation:

Let three consecutive positive integers be n, n + 1 and n + 2. ... If n = 3p + 2, then n + 1 = 3p + 2 + 1 = 3p + 3 = 3(p + 1) is divisible by 3. So, we can say that one of the numbers among n, n + 1 and n + 2 is always divisible by 3.

Answer 2

Answer:

let the integer be 3x , 3x+1 , 3x+2

then 3x is divisible by 3 except the others

similarly if we take 9x,9x+1,9x+2

then9x will be divisible except the others

Step-by-step explanation:

hope it works