Prove that only one number n-1,n+1,n+5 is divisible by 3
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Answered by
0
Given numbers,
n-1,n+1 and n+5
Put n = 1,
n-1 = 1-1 = 0
n+1 = 1+1 = 2
n+5 = 1+5 = 6 is divisible by 3
Put n = 2,
n-1 = 2-1 = 1
n+1 = 2+1 = 3 is divisible by 3
n+5 = 2+5 = 7
So, one and only one out of n-1, n+1 and n+5 is divisible by 3.
Hence proved
n-1,n+1 and n+5
Put n = 1,
n-1 = 1-1 = 0
n+1 = 1+1 = 2
n+5 = 1+5 = 6 is divisible by 3
Put n = 2,
n-1 = 2-1 = 1
n+1 = 2+1 = 3 is divisible by 3
n+5 = 2+5 = 7
So, one and only one out of n-1, n+1 and n+5 is divisible by 3.
Hence proved
Answered by
3
We have no. Like n-1,n+1,n+5.
Put n=1
n-1=1-1=0
n+1=1+1=2
n+5=1+5=6
So six is divisible by 3
So we can say that only one no. Is divisible by 3
Henced proved
Put n=1
n-1=1-1=0
n+1=1+1=2
n+5=1+5=6
So six is divisible by 3
So we can say that only one no. Is divisible by 3
Henced proved
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