prove that only one of the numbers n , n+1 ,n+2 is divisible by 3 where n is any positive integer. explain
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n=3q divisible by 3
n=3q+1
n=3q+2
n+1=3q+1
n+1=(3q+1)+1=3q+2
n+1=(3q+2)+1=3q+3 divisible by 3
n+2=3q+2
n+2=(3q+1)+2=3q+3 divisible by 3
n+2=(3q+2)+2=3q+4
n=3q+1
n=3q+2
n+1=3q+1
n+1=(3q+1)+1=3q+2
n+1=(3q+2)+1=3q+3 divisible by 3
n+2=3q+2
n+2=(3q+1)+2=3q+3 divisible by 3
n+2=(3q+2)+2=3q+4
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Hello....
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Hence, we conclude that only one of the numbers n, n+1, n+ 2 is divisible by 3 where n is any positive integer....
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