Question

prove that parallelogram circumscribing a circle is rectangle​

Answer 1

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Answer 2

Answer:

Let ABCD is a parallelogram and side AB touch the circle at point P , side BC at point Q, side CD at point R and side AD at point S. Let O be the center of circle. To prove that: ABCD is a rectangle. Reason: Radius is perpendicular to tangent.

In the parallelogram ABCD the angles A en C are equal. Because the quadrangle ABCD is inscribed in a circle A + C =180. So A = C = 90. And that is sufficient for ABCD to be a rectangle.

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