Question

prove that perpendicular at the point of contact to the tangent to a circle passes through centre of circle

Answer 1

HOPE IT HELPS YOU☺☺☺

Answer 2

Answer:

Step-by-step explanation:

Given :

Let a Circle with centre O and AB be the tangent intersecting circle at point P

To Prove :

OP ⊥ AB

Proof :

We know that tangent of Circle is perpendicular to radius at point of contact

Hence , OP ⊥ AB

So , ∠OPB = 90° -----> 1

Assume Some point x

Such that XP ⊥ AB

Hence , XPB = 90° -------> 2

From (1) and (2)

∠OPB = ∠XPB = 90°

Which is only possible when line XP passes through O

Therefore , perpendicular to the tangent passes through Centre

Please mark as brainliest answer.