prove that perpendicular drawn from point of contact passes through centre of the circle
Answers
Answered by
3
Let O be the center of the circle.
AB is the tangent drawn touching the circle at A.
Draw AC perpendicular AB at point A,such that the point C lies on the given circle.
OAB=90°(Radius of the circle is perpendicular to the tangent)
Given CAB=90°.
angle OAB=angle CAB.
This is possible only when centre O lies on the line AC.
AB is the tangent drawn touching the circle at A.
Draw AC perpendicular AB at point A,such that the point C lies on the given circle.
OAB=90°(Radius of the circle is perpendicular to the tangent)
Given CAB=90°.
angle OAB=angle CAB.
This is possible only when centre O lies on the line AC.
Attachments:
Similar questions