Prove that:
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Answer:
Step-by-step explanation:
Cos(A - π) + Sin(A + π/2)
We know that Cos(A - B) = CosACosB - SinASinB
Sin(A+B) = SinACosB + CosASinB
=> CosACosπ - SinASInπ + SinACosπ/2 + CosASinπ/2
We know that Cos 90 = 0 and Cos180 = - 1 and Sin90 = 1 and Sin180 = 0.
=> CosA(-1) + SinA(0) + SinA(0) + CosA(1)
=> - CosA + CosA
=> 0
= R.H.S
Hence proved.
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