Prove that quaternion group under multiplication is non abelian
Answers
Answered by
0
Answer:
Since, all 4 properties of group are satisfied G is a group. Thus, G is commutative. A commutative group is called as an abelian group. Thus, cube roots of unity form a finite abelian group under multiplication.
Answered by
1
Note :
Group : An algebraic system (G,*) is said to be a group if the following condition are satisfied :
- G is closed under *
- G is associative under *
- G has a unique identity element
- Every element of G has a unique inverse in G
Moreover , if a group (G,*) also holds commutative property , then it is called commutative group or abelian group .
Cyclic group : A group G is called a cyclic group , if there exists an element a ∈ G , such that every element x ∈ G can be written as x = aⁿ for some integer n . And the element a is called the generator of G .
Solution :
Please refer to the attachments .
Attachments:
Similar questions