Prove that root 1-sin theta/1+sin theta=sec theta-tan theta
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Answered by
92
Answer:
=1 + SinA / CosA
Step-by-step explanation:Firstly consider L.H.S ; NOW rationalise
√ 1 +SinA √ 1+ SinA
--------------- x ----------------
√ 1- SinA √1 + SinA
√ ( 1+ SinA)² 1+ SinA
------------------ = --------------
√ 1² - Sin²A Cos A
Now consider RHS
= Sec A + Tan A
=1/ Cos A + SinA / CosA
=1 + SinA / CosA
Hence proved ....
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