Question

Prove that root 2 is irrational number
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Answer 1

Answer:

If √2 could be written as a rational number, the consequence would be absurd. So it is true to say that √2 cannot be written in the form p/q. Hence √2 is not a rational number. Thus, Euclid succeeded in proving that √2 is an Irrational number.

Answer 2

Step-by-step explanation:

to prove= root2 is irrational no.

proof= let us contrary assume that root 2 is rational no.

proof= let us contrary assume that root 2 is rational no. it can written in the form of p/ q form in which ,p and w is any integer.

proof= let us contrary assume that root 2 is rational no. it can written in the form of p/ q form in which ,p and w is any integer. root 2 = p/ q

proof= let us contrary assume that root 2 is rational no. it can written in the form of p/ q form in which ,p and w is any integer. root 2 = p/ q square both side

proof= let us contrary assume that root 2 is rational no. it can written in the form of p/ q form in which ,p and w is any integer. root 2 = p/ q square both side ( root 2)square =( p/ q) square

proof= let us contrary assume that root 2 is rational no. it can written in the form of p/ q form in which ,p and w is any integer. root 2 = p/ q square both side ( root 2)square =( p/ q) square root cut by square

proof= let us contrary assume that root 2 is rational no. it can written in the form of p/ q form in which ,p and w is any integer. root 2 = p/ q square both side ( root 2)square =( p/ q) square root cut by square 2 = p^2/q^2

proof= let us contrary assume that root 2 is rational no. it can written in the form of p/ q form in which ,p and w is any integer. root 2 = p/ q square both side ( root 2)square =( p/ q) square root cut by square 2 = p^2/q^2 2q^2= p^2

proof= let us contrary assume that root 2 is rational no. it can written in the form of p/ q form in which ,p and w is any integer. root 2 = p/ q square both side ( root 2)square =( p/ q) square root cut by square 2 = p^2/q^2 2q^2= p^2 since ,2q^2 &p^2 is rational

proof= let us contrary assume that root 2 is rational no. it can written in the form of p/ q form in which ,p and w is any integer. root 2 = p/ q square both side ( root 2)square =( p/ q) square root cut by square 2 = p^2/q^2 2q^2= p^2 since ,2q^2 &p^2 is rational hence, our consumption was wrong root 2 is an irrational no.