Question

prove that root 2 is not a rational number

Answer 1

Answer:

Euclid's proof starts with the assumption that √2 is equal to a rational number p/q.

√2=p/q

Squaring both sides,

2=p²/q²

The equation can be rewritten as

2q²=p²

From this equation, we know p² must be even (since it is 2 multiplied by some number). Since p² is an even number, it can be inferred that p is also an even number.

Since p is even, it can be written as 2m where m is some other whole number. This is because the definition of an even number is it can be written as 2 multiplied by a whole number. Substituting p=2m in the above equation:

2q²=p²=(2m)²=4m²

or

2q²=4m²

Dividing both sides of the equation by 2:

q²=2m²

By the same reasoning as before, q² is an even number (since it is written as 2 multiplied by some number). So q is an even number. Let q=2n where n is some whole number. We had assumed √2 to be equal to p/q. So:

√2=p/q=2m/2n

By canceling 2 in the numerator and the denominator of the Right hand side,

√2=m/n

We now have a fraction m/n simpler than p/q.

However, we now find ourselves in a position whereby we can repeat exactly the same process on m/n, and at the end of it, we can generate a simpler function, say g/h. This fraction can be put through the same process again, and the new fraction, say, e/f will be simpler again.

But we know that rational number cannot be simplified indefinitely. There must always be a simplest rational number and the original assumption that √2 is equal to p/q does not obey this rule.

So it can be stated that a contradiction has been reached.

If √2 could be written as a rational number, the consequence would be absurd. So it is true to say that √2 cannot be written in the form p/q. Hence √2 is not a rational number.

Thus, Euclid succeeded in proving that √2 is an Irrational number.

Answer 2

√2 is a irrational number

Given,

√2

To Find,

Find that √2 is not a rational number

Solution,

• When a number is multiplied by itself, the result is the original number; this is known as the square √2, which is a symbol for the √2 Uncertainty surrounds the real value of 2.
• Since 2 has a non-terminating and non-repeating decimal expansion, it has an endless length. The definition of an irrational number is any number with a non-terminating and non-repeating decimal expansion. Consequently, 2 is an irrational number.

If possible , let √2, be a rational number

and its simplest form be a/b then, a and b are integers having no common factor other than 1 and b=0

Now, √2= a/b

or, 2= a²/b² ( squaring both sides)

or, 2b²= a²........(i)

2 divides a²

and from that we say that 2 divides a

Let a=2c for some integer c

Putting a=3c in (i), we get

or, 2b²= 4c²

or, b²= 2c²

2 divides b²

So, 2 divides a

Thus 2 is a common factor of a and b

This contradicts the fact that a and b have no common factor other than 1.

The contradiction arises by assuming √2 is a rational number

Hence, √2 is a irrational (Proved)

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