prove that root 3+2 root 5 is irrational
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Answered by
51
let 3 + 2 root 5 is rational
therefore 3 + 2 root 5=a/b(where a and b are any integer )
root 5=a-3/2b
be cos a-3/2b is rational
therefore root 5 will also be rational
but we know that,
root 5 is irrational
that is our supposition is wrong
that is 3+2 root 5 is irrational
therefore 3 + 2 root 5=a/b(where a and b are any integer )
root 5=a-3/2b
be cos a-3/2b is rational
therefore root 5 will also be rational
but we know that,
root 5 is irrational
that is our supposition is wrong
that is 3+2 root 5 is irrational
Answered by
41
Let us assume that 3+2√5 is rational.
Such that there exists two integers a and b such that 3+2√5 = a/b.
2√5 = a/b - 3
2√5 = a - 3b /b
√5 = a - 3b /2b
We know that √5 is irrational.
But it is equal to a-3b/2b where a and n are integers and so it is rational.
But this contradicts the fact that √5 is irrational.
Thus contradiction occurred because of our wrong assumption that 3+2√5 is rational.
HENCE 3+2√5 IS IRRATIONAL.
:)
Such that there exists two integers a and b such that 3+2√5 = a/b.
2√5 = a/b - 3
2√5 = a - 3b /b
√5 = a - 3b /2b
We know that √5 is irrational.
But it is equal to a-3b/2b where a and n are integers and so it is rational.
But this contradicts the fact that √5 is irrational.
Thus contradiction occurred because of our wrong assumption that 3+2√5 is rational.
HENCE 3+2√5 IS IRRATIONAL.
:)
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